top button
Flag Notify
    Connect to us
      Site Registration

Site Registration

LTE: Can anyone please explain that how COUNT value is used to cipher a PDCP SDU ?

+5 votes
1,316 views

One more related question : Does the same COUNT value used for both integrity protection and ciphering of SDU ?

posted Nov 21, 2013 by Vikram Singh

Share this question
Facebook Share Button Twitter Share Button LinkedIn Share Button

2 Answers

+6 votes

1> Count is calculated From the Sequence Number(SN) and Hyper Frame Number(HFN) of the PDU.
2> As the count is used to calculate the ciphering key and integrity key so count is same for both Key generation .

Ciphering Key generation

f8 Algorithm is used for this.
Please see this figure for inputs and outputs of this algorithm
enter image description here

Integrity Key generation

f9 Algorithm is used for this
Please see this figure for inputs and outputs of this algorithm

enter image description here

For Security algorithms u can refer to Spec 35.201
Best book is LTE Security by Günther Horn

answer Nov 21, 2013 by Sachidananda Sahu
+5 votes

I answered it in below provided link. I found the same question there and answered it there. So I request you to follow up there.

http://tech.queryhome.com/25726/why-is-pdcp-sdu-size-maximum-kept-as-8188-octets

answer Apr 2, 2014 by Hiteshwar Thakur
Similar Questions
+2 votes

What are the steps involved to do integrity verification ?

+4 votes

In 3GPP 36.323 specification mentioned that the size of PDCP SDU is 8188 Octets. From where this number comes ?

+4 votes

Which factor derives this 7 bits or 12 bits long PDCP SN for PDCP data PDU carrying user data ?
Is it run time configurable for an UE ? or one time configuration.

...