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Unable to understanding map usage in perl

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I am looking at the following code someone wrote and I have difficultly in understand map usage. Can somebody please explain how does the following code work?

print OUT2 join( ',', map { $_=~ s/"/'/g; ""$_"" } @data )
posted Jul 24, 2013 by anonymous

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1 Answer

+1 vote

Here is the documentation for map from 'perldoc -f map':

map BLOCK LIST
map EXPR,LIST
Evaluates the BLOCK or EXPR for each element of LIST (locally setting $_ to each element) and returns the list value composed of the results of each such evaluation.

In your case, BLOCK is

{ $_=~ s/"/'/g; ""$_"" } 

and LIST is @data. Therefore, each element of @data is aliased to $_, the substitution s//"/'/g is performed on it, which changes all double-quote characters to single-quote apostrophes, Then, the second 'line' of the BLOCK is evaluated and pushed onto the result list, which puts the transformed string between double-quotes. The resulting list is joined with '.' characters and printed to the OUT2 file stream.

answer Jul 24, 2013 by anonymous
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