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How to create a SQL table if table does not exists using php?

+1 vote
290 views

I am tring to create a new table into the database if the table name given is not present in database using Php .
This is the code that I am using .

  $conn = mysql_connect($dbhost, $dbuser, $dbpass);
    if(!$conn)
    {
            die('Failed to connect to server: ' . mysql_error());
            exit;
    }
    $db_selected = mysql_select_db($dbname);
    if(!$db_selected)
    {
           $db_selected = " CREATE DATABASE $dbname ";
    }
    $usertb1 = mysql_query("select 1 from $usertb LIMIT 1");
    if( $usertb1 !== FALSE )
    {
           $sql = "CREATE TABLE IF NOT EXISTS $usertb ( uid INT(20) AUTO_INCREMENT UNIQUE KEY NOT NULL,name VARCHAR(40),email varchar(40) PRIMARY KEY NOT NULL)";
    }
    $typetb1 = mysql_query("select 1 from $typetb LIMIT 1");
    if( $typetb1 !== FALSE)
    {
           $sql1 = "CREATE TABLE IF NOT EXISTS $typetb( uid INT(20) NOT NULL, type ENUM('WEB','APP','CART') NOT NULL ,unsubscribe TINYINT(1) NOT NULL,bounce TINYINT(1) NOT NULL,complaint TINYINT(1) NOT NULL, PRIMARY KEY (uid,type), FOREIGN KEY(uid) WHERE promo_user(uid))";
    }
posted May 18, 2017 by Ajay Shetty

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